9=x^2/(0,003-x)(0,003-x)

Solution for 9=x^2/(0,003-x)(0,003-x) equation:

9=x^2/(0.003-x)(0.003-x)

We move all terms to the left:

9-(x^2/(0.003-x)(0.003-x))=0


Domain of the equation: (0.003-x)(0.003-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)(0.003-x)!=-0.003

x∈R


We add all the numbers together, and all the variables

-(x^2/(-1x+0.003)(-1x+0.003))+9=0

We multiply parentheses ..

-(x^2/(+x^2-0.003x-0.003x+9.0E-6))+9=0

We multiply all the terms by the denominator


-(x^2+9*(+x^2-0.003x-0.003x+9.0E-6))=0


We calculate terms in parentheses: -(x^2+9*(+x^2-0.003x-0.003x+9.0E-6)), so:

x^2+9*(+x^2-0.003x-0.003x+9.0E-6)

We multiply parentheses

x^2+9x^2+0x+0x+220.180828105-54

We add all the numbers together, and all the variables

10x^2+2x+166.180828105

Back to the equation:

-(10x^2+2x+166.180828105)


We get rid of parentheses

-10x^2-2x-166.180828105=0

a = -10; b = -2; c = -166.180828105;
Δ = b2-4ac
Δ = -22-4·(-10)·(-166.180828105)
Δ = -6643.2331242
Delta is less than zero, so there is no solution for the equation